(x^3-3x-52)/(x-4)

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Solution for (x^3-3x-52)/(x-4) equation:


D( x )

x-4 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

(x^3-(3*x)-52)/(x-4) = 0

(x^3-3*x-52)/(x-4) = 0

x^3-3*x-52 = 0

x^3-3*x-52 = 0

{ 1, -1, 2, -2, 4, -4, 13, -13, 26, -26, 52, -52 }

1

x = 1

x^3-3*x-52 = -54

1

-1

x = -1

x^3-3*x-52 = -50

-1

2

x = 2

x^3-3*x-52 = -50

2

-2

x = -2

x^3-3*x-52 = -54

-2

4

x = 4

x^3-3*x-52 = 0

4

x-4

x^2+4*x+13

x^3-3*x-52

x-4

4*x^2-x^3

4*x^2-3*x-52

16*x-4*x^2

13*x-52

52-13*x

0

x^2+4*x+13 = 0

DELTA = 4^2-(1*4*13)

DELTA = -36

DELTA < 0

x in { 4}

x-4 = 0

1 = 0

x belongs to the empty set

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